A liquid exerts a pressure of 100,695 Pa on an object when it is 735 cm below the liquid surface. What is the density of the liquid? (Take g =10ms⁻²). 

Given,
Pressure = 100,695 Pa
Height (h)= 735 cm = 7.35 m
g=10ms⁻²

Pressure = $\rho gh$
 $\therefore$  $\rho = \frac{P}{gh}= \frac{100695}{7.35}$

$\rho = 13700 kg/m^3$

Therefore, the density of the liquid must be 13700 kgm^-3.