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A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross-section $A_{1}$ and $A_{2}$ , are $v_{1}$ and $v_{2}$ respectively. The difference in the levels of the liquid in the two vertical tubes is h.

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The volume of the liquid flowing through the tube in unit times is $A_{1} v_{1}$ .

$v_{2} - v_{1} = \sqrt{2 g h}$

$v_{2}^{2} - v_{1}^{2} = 2 g h$

The energy per unit mass of the liquid is the same in both sections of the tube.

answer is A, C, D.

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Detailed Solution

Equation of continuity $A_{1} v_{1} = A_{2} v_{2}$
Apply Bernoullis theoram

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