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A liquid in container is compressed from (2 atm, 1 litre) to (10 atm, 0.5 litre) isothermally where it absorb 200 J heat and work done on the system is 500 J. Calculate the enthalpy change of process in KJ. $(1 a t m \times 1 l i t = 100 J)$ .

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Detailed Solution

$Δ U = q + w = 200 + 500 = 700 J$

$Δ H = Δ U + (P_{2} V_{2} - P_{1} V_{1}) \times 100 = 700 + (10 \times 0.5 - 2 \times 1) \times 100 = 1000 J = 1 K J$

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