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A liquid is kept in a cylindrical jar, which is rotated about the cylindrical axis. The liquid rises at its sides. The radius of the jar is ‘r’, and speed
of rotation is ‘ $ω$ ’. The difference in height at the centre and the sides of the jar is

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$\frac{r^{2} ω^{2}}{2 g}$

$\frac{r^{2} ω^{2}}{g}$

$\frac{g}{r^{2} ω^{2}}$

$\frac{2 g}{r^{2} ω^{2}}$

answer is B.

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Detailed Solution

Difference in potential energy = Rotational

$Kinetic energy ∴ mg (h_{1} - h_{2}) = \frac{1}{2} {Iw}^{2}$

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