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A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at the side. If the radius of the vessel is 5 cm and the speed of rotation is 4 rev/s, then the difference in the height of the liquid at the centre of the vessel and its sides is

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16 cm

2 cm

40 cm

4 cm

answer is A.

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Detailed Solution

Given R = 5 cm, w = 2p (4) rad/s. Using $y = \frac{ω^{2} x^{2}}{2 g}$ the required level difference is y. When x = R, $y = \frac{{(8 π)}^{2} (5 \times 10^{- 2})}{2 \times 9.8} = 16 c m$ .

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