A liquid of density 0.85 g/cm³ flows through a calorimeter at the rate of 8.0 cm³/s. Heat is added by means of a 250 W electric heating coil and a temperature difference of 15^oC is established in steady-state conditions between the inflow and the outflow points of the liquid. The specific heat for the liquid will be

This is a problem on 'flow calorimeter' used to measure specific heat of a liquid.
Amount of heat supplied to the water per second by the heating coil $={\mathrm{Q}}_{\mathrm{S}}=250\mathrm{J}=\frac{250}{4186}\mathrm{kcal}$

The volume of liquid flowing out per second $1=8.0{\mathrm{cm}}^3$

                                                                        $=8\times {10}^{-6}{\mathrm{m}}^3$

Mass of this liquid $=\left(0.85\right)\times 1000\times 8\times {10}^{-6}\mathrm{kg}$

Temperature rise of this mass of liquid $={15}^{\circ }\mathrm{C}$

Hence, $\frac{250}{4186}=\mathrm{mst}=0.85\times 8\times {10}^{-3}\times \mathrm{s}\times 15$

Hence, $s=\frac{250\times {10}^3}{4186\times 0.85\times 8\times 15}=0.6kcal/kgK$