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A liquid of mass m and specific heat c is heated to temperature T. Another liquid of mass (m/2) and specific heat 2c is heated to a temperature 2T. If these two liquids are mixed, the resulting temperature of the mixture is

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(3/5) T

(3/2)T

(8/5)T

(2/3)T

answer is D.

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Detailed Solution

$Q_{l o s t} = Q_{g a i n e d}$ $m_{1} s_{1} {(∆ T)}_{1} = m_{2} s_{2} {(∆ T)}_{2}$ $(m) (c) (x - T) = (\frac{m}{2}) (2 c) (2 T - x)$ $x - T = 2 T - x$

$x = \frac{3 T}{2}$

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