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A liquid stands at the plane level in the U-tube when at rest. If areas of cross-section of both the limbs are equal, what will be the difference in heights h of the liquid in the two limbs of U-tube, when the system is given an acceleration a in horizontal direction towards right as shown?

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zero

$\frac{{Lg}^{2}}{a^{2}}$

$\frac{Lg}{a}$

$\frac{La}{g}$

answer is B.

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Detailed Solution

$ρgh = ρaL ∴ h = \frac{aL}{g}$

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