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Q.

A Lloyd’s mirror of length 5 cm is illuminated with monochromatic light of wavelength $λ (= 6000 \overset{0}{A})$ from a source 5 cm from its near edge. Find the fringe width on a screen 120 cm from the source . The perpendicular distance of the source from the mirror is 1 mm.

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a

36 cm

b

0.036 cm

c

3.6 cm

d

0.36 cm

answer is D.

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Detailed Solution

$In a plane mirror, image is formed behind it as the object is in front of it . So, d = 2 mm = 0.2 cm, D = 120 cm, λ = 6000 \overset{0}{A} = 6000 \times 10^{- 8} cm . Therefore, fringe width, β = \frac{λD}{d} = \frac{6 \times 10^{- 5} \times 120}{0 .2} = 0.036 cm$

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