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A long capillary tube is immersed vertically in water such that the height of liquid column is x. When this arrangement is taken into a mine where the gravity is $\frac{3}{4} th$ of the gravity on the surface of earth, new capillary height is

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$\frac{4 x}{3}$

$\frac{3 x}{4}$

$\frac{3 x}{2}$

$\frac{2 x}{3}$

answer is A.

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Detailed Solution

Surface tension $T = \frac{hr ρ g}{2} = constant$
hg = constant
$x g = h_{2} (\frac{3 g}{4})$
$h_{2} = \frac{4 x}{3}$

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