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Q.

A long conducting wire AH is moved over a conducting triangular wire CDE with a constant velocity v in a uniform magnetic field Bdirected into the plane of the paper. Resis­tance per unit length of each wire is r. Then

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a

a decreasing anticlockwise induced current will flow in the closed loop

b

an increasing anticlockwise induced current will flow in the closed loop

c

a constant anticlockwise induced current will flow in the closed loop

d

a constant clockwise induced current will flow in the closed loop

answer is D.

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Detailed Solution

Magnetic flux in direction through the coil is increasing. Therefore, induced current will produce magnetic field in  direction. Thus, the current in the loop is anticlockwise. Magnitude of induced current at any instant of time is I=eR=Bv(FG)ρ(FG+GD+DF) When the wire AH moves downwards,  FG,GD and DF all increase in the same ratio. Therefore, i is constant.

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