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A long constantan wire is connected across the terminals of an ideal battery. If the wire is cut in to two equal pieces and one of them is now connected to the same battery, what will be the mobility of free electrons now in the wire compared to that in the first case?

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four times that of previous value

double that of previous value

half that of previous value

same as that of previous value

answer is B.

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Detailed Solution

$μ = \frac{v_{d}}{E}$ $V_{d} = \frac{i}{n e A}$ , V = EL, $μ = \frac{1}{n e ρ}$

independent of length.

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