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A long horizontal rod has a bead which can slide along its length and is initially placed at a distance L from one end A of the rod. The rod is set in angular motion about A with a constant angular acceleration $α$ . If the coefficient of friction between the rod and bead is $μ$ and gravity is neglected then the time after which the bead starts slipping is

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$\sqrt{\frac{μ}{α}}$

$\frac{μ}{\sqrt{α}}$

$\frac{1}{\sqrt{μ α}}$

Infinitesimal

answer is A.

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Detailed Solution

$N = m r α, μ N = m r ω^{2}, ω = α t$

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