A long solenoid has 100 turns per cm and carries a current i. The magnetic field at its centre is 6x10^–2Wb/m². Another long solenoid has 400 turns per cm and it carries a current i/2. The value of the magnetic field at its centre is

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$8 \times 10^{- 5} Web / m^{2}$

$6 \times 10^{- 4} Web / m^{2}$

$12 \times 10^{- 2} Web / m^{2}$

$10 \times 10^{- 2} Web / m^{2}$

answer is B.

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Detailed Solution

${\begin{array}{l} B_{} = μ_{0} ni; B^{'} = μ_{0} n^{'} i / 2; \frac{B_{1}}{B_{2}} = \frac{n_{1}}{n_{2}} \frac{i}{i / 2} \\ \frac{6 \times 10^{- 2}}{B} = \frac{100}{400} \times 2; B = 12 \times 10^{- 2} T \end{array}}^{}$

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