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Q.

A long solenoid of 50 cm length having 10 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is: $(μ = 4 π \times 10^{- 7} T m A^{- 1})$

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a

$3.14 \times 10^{- 4} T$

b

$6.28 \times 10^{- 5} T$

c

$3.14 \times 10^{- 5} T$

d

$6.28 \times 10^{- 4} T$

answer is B.

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Detailed Solution

$\begin{array}{l} B = μ_{0} \frac{N}{l} I \\ = 4 π \times 10^{- 7} \times \frac{10}{0.5} \times 2.5 \\ = 6.28 \times 10^{- 5} T \end{array}$

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