A long straight wire of length 2 m and mass 250 g is suspended horizontally in a uniform horizontal magnetic field of 0.7 T. The minimum amount of current flowing through the wire will be (g = 9.8 ms-2).

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A long straight wire of length 2 m and mass 250 g is suspended horizontally in a uniform horizontal magnetic field of 0.7 T. The minimum amount of current flowing through the wire will be (g = 9.8 ms^-2).

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2.75A

1.75A

2.25A

2.45A

answer is D.

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Detailed Solution

mg = ilB
$\begin{array}{l} 250 \times 10^{- 3} \times 9.8 = i \times 2 \times 0.7 \\ \Rightarrow i = \frac{0.250 \times 9.8}{2 \times 0.7} \\ \Rightarrow i = 1.75 A \end{array}$