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A long wire X, carrying a current of 2A is placed parallel to another long wire Y. The wire Y carries a current of 3A. The distance between two wires is 5 cm and currents flow in the same direction. The force acting per unit length on the wire Y is

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$1.2 \times 10^{- 5} N$ directed towards wire $X$

$1.2 \times 10^{- 4} N$ directed away from wire $X$

$1.2 \times 10^{- 4} N$ directed towards wire $X$

$2.4 \times 10^{- 5} N$ directed towards wire $X$

answer is D.

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Detailed Solution

$F_{X Y} = F_{Y X} = F$

$F = \frac{μ_{0} i_{1} i_{2}}{2 π r} = (2 \times 10^{- 7}) \frac{2 \times 3}{5 \times 10^{- 2}}$

$= 2.4 \times 10^{- 5} N$

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