A loop carrying current i lies in the xy-plane in the figure. The unit vector k^ is coming out of the plane of the paper. The magnetic moment of the current loop is

M=l×Area of loop=l×a2+πa4×2×4 =l×a2π2+1π2+1a

A loop carrying current i lies in the xy-plane in the figure. The unit vector k^ is coming out of the plane of the paper. The magnetic moment of the current loop is

M=l×Area of loop=l×a2+πa4×2×4 =l×a2π2+1π2+1a

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A loop carrying current $i$ lies in the xy-plane in the figure. The unit vector $\hat{k}$ is coming out of the plane of the paper. The magnetic moment of the current loop is

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$a^{2} i \hat{k}$

$(\frac{π}{2} + 1) a^{2} i \hat{k}$

$- (\frac{π}{2} + 1) a^{2} i \hat{k}$

$(2 π + 1) a^{2} i \hat{k}$

answer is B.

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$M=l×Area of loop=l× [a^{2} + \frac{πa}{4×2} ×4] {=l×a}^{2} [\frac{π}{2} +1] (\frac{π}{2} + 1) a$

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A loop carrying current i lies in the xy-plane in the figure. The unit vector k^ is coming out of the plane of the paper. The magnetic moment of the current loop is

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A loop carrying current $i$ lies in the xy-plane in the figure. The unit vector $\hat{k}$ is coming out of the plane of the paper. The magnetic moment of the current loop is