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A loop of flexible conducting wire of length 0.5m lies in a magnetic field of 1T perpendicular to the plane of the loop. If loop carries a current of 1.57A, it turns in to a circle Then find tension developed in the wire

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0.125 dyne

1.125 N

1.25 dyne

0.125 N

answer is D.

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Detailed Solution

$T = \frac{BiL}{2 π}$

$= \frac{1 \times 1.57 \times 0.5}{2 \times 3.14} = 0.125 N$

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