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Q.


A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot.

Suppose the bulb drawn in is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective? 
 


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a

15 19  

b

4 19  

c

3 4  

d

1 5    

answer is A.

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Detailed Solution

It is given a lot of 20 bulbs contain 4 defective ones.

When drawn bulb is not defective and not replaced, total number bulbs left=20 - 1=19
Total number of defective bulbs = 4
Number of non-defective bulbs= 19 - 4= 15
Now, the probability of an event E is given as-
P(E)= Number of outcomes favourable to E Number of all possible outcomes of the experiment  
Therefore, the probability of getting a non-defective bulb is-
P getting a non-defective bulbs = Number of non-defective bulbs Total number of bulbs = 15 19  
Hence, 15 19   is the probability of getting a non-defective bulb.
Hence option (1) is correct.
  
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