A lot of 20 bulbs contain 5 defective ones. Suppose the bulb drawn from the lot is found to be defective and removed from the lot. Another bulb is drawn. Find the probability that it is not defective.

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A lot of 20 bulbs contain 5 defective ones. Suppose the bulb drawn from the lot is found to be defective and removed from the lot. Another bulb is drawn. Find the probability that it is not defective.

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Detailed Solution

Given that in a lot of 20 bulbs, it contains 5 defective ones and a bulb drawn from the lot is found to be defective and removed from the lot.
We need to find the probability that the next bulb drawn is not defective.
Probability of an event E is defined as:

P (E) = \frac{Number of favorable outcomes}{Total number of possible outcomes}

There are 20 bulbs in a lot but since one of them is removed, therefore, we are left with 19 bulbs.
Therefore,the total number of possible outcomes is 19.
Defective bulbs are 5.
Therefore, non-defective bulbs are: