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Q.

A machine gun fires a bullet of mass 40g with a velocity 1200ms^-1. The man holding it can exert a maximum force of 144 N on the gun. Number of bullets he can fire per second at the most is ___

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answer is 3.

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Detailed Solution

u = Velocity of bullet
$\frac{d m}{d t} =$ Mass fired per second by the gun
$\frac{d m}{d t} =$ Mass of bullet $(m_{B}) \times$ Bullets fired per sec (N)
Maximum force that man can exert,
$F = u (\frac{d m}{d t})$
$⸫ F = u \times m_{B} \times N$

$\Rightarrow N = \frac{F}{m_{B} \times u} = \frac{144}{40 \times 10^{- 3} \times 1200} = 3$

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A machine gun fires a bullet of mass 40g with a velocity 1200ms-1. The man holding it can exert a maximum force of 144 N on the gun. Number of bullets he can fire per second at the most is ___