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A machine gun of mass 10kg, fires 10gm bullets at the rate of two every second. Each bullet comes out with a velocity of 100 m/s. The velocity of recoil of the gun at the end of the fourth second, after firing starts is

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3.2 m/s

1.6 m/s

2.0 m/s

0.8 m/s

answer is B.

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Detailed Solution

_{$V = \frac{m n u}{M}$}

_{$= \frac{10 \times 10^{- 3} \times 8 \times 100}{10} = 0.8 m s^{- 1}$}

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