A magnet of length 14 cm and magnetic moment $μ_{0}$ is broken into two parts of length 6 cm and 8 cm. They are put at right angles to each other with the opposite poles together. The magnetic dipole moment of the combinations:

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$\frac{μ}{1.4}$

$μ$

$1.4 μ$

$2.8 μ$

answer is A.

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Detailed Solution

The pole strength remains unchanged but distance berween the poles becomes = $\sqrt{8^{2} + 6^{2}} = 10 cm$ , so magnetic dipole moment of the combination,

$μ' = m x 10 = m x \frac{14}{14} x 10$

$= \frac{m x 14}{1.4} = \frac{μ}{1.4}$

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