A magnet of length 2L and moment ‘M’ is axially cut into two equal halves ‘P’ and ‘Q’. The piece ‘P’ is bent in the form of semi circle and ‘Q’ is attached to it as shown. Its moment is

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$\frac{M}{2 π}$

$\frac{M (2 + π)}{2 π}$

$\frac{Mπ}{(2 + π)}$

$\frac{M}{π}$

answer is C.

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Detailed Solution

In the arrangement magnetic moment of P is
$M_{1} = \frac{2 \frac{M}{2} \sin \frac{π}{2}}{π} = \frac{M}{π}$ and magnetic moment of
Q is $M_{2} = \frac{M}{2}$
$∴$ Resultant magnetic moment $M_{r} = M_{1} + M_{2} = \frac{M}{π} + \frac{M}{2} = \frac{M (π + 2)}{2 π}$

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