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Q.

A magnetic field of 4×103K^T exerts a force of (4i^+3j^)×1010N on a particle of charge 109C and going in X-Y plane. The velocity of the charged particle is

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a

75i^100J^

b

75i^+100J^

c

100i^75J^

d

100i^+75J^

answer is B.

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Detailed Solution

F=q(V×B)

letV=(xi^+yj^)ms1

(4i^+3j^)×1010=109(xi^+yj^)×4×103k^

(4i^+3j^)=1091010(xi^+yj^)×4×103

4i^+3j^=4×102(yi^xj^)

4i^+3j^=4100(yi^xj^)

100i^+75j^=yi^xj^

y=100andx=75

V=(75i^+100j^)ms1

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