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Q.

A magnetic field of intensity 2 × 103 Am–1 produces a magnetic flux density of 1767T in an iron rod. The relative permeability of the rod, is

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a

102

b

103

c

104

d

10-3

answer is C.

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Detailed Solution

μ=BH⇒μr=Bμ0H=1767×4π×10−7×2×103=104

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