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Q.

A magnetic needle lying parallel to a magnetic field requires ‘W’ unite of work to turn it through 60°. The torque required to maintain the needle in the portion is

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a

2w

b

2w

c

3w

d

3w

answer is B.

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Detailed Solution

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Case 1: W=MBcos00cos600=MB2

Case 2:τ=MBsin600

τ=MB×32τ=3w

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