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Q.

A magnetic needle of pole strength 203 Am is pivoted at its centre. Its N-pole is pulled eastward by a string. The horizontal force required to produce a deflection of 30° from magnetic meridian (take BH = 10–4 T) is

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a

4×10−3N

b

2×10−3N

c

43×10−3N

d

23×10−3N

answer is A.

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Detailed Solution

F=2mBHTan⁡θ=2×203×10−4×13=4×10−3N

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