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A magnetising field of 1500 A/m produces a magnetic flux of 2.4 × 10^–5 wb in a bar of iron cross section 0.5 cm². Calculate the permeability

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6.2 × 10^–4 Tm/A

3.2 × 10^–4 Tm/A

2.2 × 10^–4 Tm/A

4.2 × 10^–4 Tm/A

answer is A.

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Detailed Solution

$B = \frac{ϕ}{A} = 0 .48; μ = \frac{B}{H} = 3 .2 \times 10^{- 4} Tm / A$

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