A magnetized straight wire has a magnetic moment M. It is bent into a semi circular arc, its magnetic moment becomes

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A magnetized straight wire has a magnetic moment M. It is bent into a semi circular arc, its magnetic moment becomes

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$\frac{2 π}{M}$

$2 π \frac{M}{3}$

$\frac{M}{π}$

$\frac{2 M}{π}$

answer is C.

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Detailed Solution

$M = m \times l [length of wire = l]$

For semicircle,

$π r = l \Rightarrow r = \frac{l}{π}$

$M' = m \times 2 r = m \times 2 \times \frac{l}{π} = \frac{2 M}{π}$

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