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A magnetizing force of 360Am^–1 produces a magnetic flux density of 0.6T in a ferromagnetic material. The susceptibility of the material is

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1625

1329

2105

1914

answer is B.

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Detailed Solution

$μ = \frac{B}{H} = \frac{0.6}{360} = 1.67 \times 10^{- 3} T A^{- 1} m$

$∴ {Susceptibility, χ}_{m} = \frac{μ}{μ_{0}} - 1 = \frac{1.67 \times 10^{- 3}}{4 π \times 10^{- 7}} - 1 = 1329$

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