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A man 80kg is supported by two cables as shown in the figure. Then the ratio of tensions T₁and T₂is

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$1 : \sqrt{3}$

1 : 3

$\sqrt{3} : 1$

1: 1

answer is C.

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Detailed Solution

From figure in equilibrium position
$T_{1} \sin 30^{\circ} = T_{2} \sin 60^{\circ}$
or $T_{1} \times \frac{1}{2} = T_{2} \times \frac{\sqrt{3}}{2}$
or $\frac{T_{1}}{T_{2}} = \sqrt{3}$

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