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A man buys $m$ articles at Rs. $x$ each and another $n$ articles for Rs. $y$ . If he sells all the articles at Rs. $z$ per article, frame an equation to find his profit.

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(mx + n) z - (mx + y)

(m + n) zx - (mx + y)

(m + n) z - (mx + ny)

(mn + x) z - (mx + y)

answer is C.

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Detailed Solution

Given that a man buys

m

articles at Rs.

x

each and another

n

articles for Rs.

y

and he then sells all the articles at Rs.

z

per article.
Cost price for a article = Rs

x

Cost price of

m

articles = Rs

mx

.
Cost price of other article = Rs

y

Cost price of

n

another articles = Rs

ny

Total cost price

=

mx + ny

Selling price of a article = Rs

z

∴ Selling Price for

(m + n)

articles

=

z (m + n)

Profit

=

Selling price

-

Cost price

\Rightarrow

Profit

= z (m + n) - (mx + ny)

Thus, the equation to represent the profit is

z (m + n) - (mx + ny)

.
Therefore, the correct option is 3.

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