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A man can row a boat at a velocity of 10 m/s in still water. Speed of water in the river is 5 m/s. If the man wishes to cross the river in the minimum possible time, the drift produced is [width of river = 1 km]

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500 m

250 m

375 m

450 m

answer is A.

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Detailed Solution

If the man wishes to cross the river in the minimum possible time, then he should row the boat in a direction perpendicular to the direction of motion.

$∴ t_{\min} = \frac{d}{V_{b / ω}}$

$∴ {Drift = BC = V}_{ω} \times t_{\min} = 5 \times \frac{1000}{10} m = 500 m$

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