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A man can swim directly a stream of width 100 m in 4 minutes, when there in no current of water and in 5 minutes when there is current of water. The velocity of the current of water in the stream is

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5ms^-1

0.25ms^-1

15ms^-1

2.5ms^-1

answer is D.

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Detailed Solution

$t_{1} = \frac{d}{V_{B}}, t_{2} = \frac{d}{\sqrt{V_{B}^{2} - V_{W}^{2}}}$

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