A man covers a distance on a scooter. Had he moved 3 kmph faster he would have taken 40 minutes less? If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance is:

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30 km.

45 km.

40 km.

50 km.

answer is C.

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Detailed Solution

Let speed is S km.

$\frac{S (S + 3)}{3} \times t = \frac{S (S - 2)}{2} \times 40$

$\begin{array}{l} \frac{S (S + 3)}{3} \times 40 = \frac{S (S - 2)}{2} \times 40 \\ \frac{(S + 3)}{3} = \frac{(S - 2)}{2} \\ 2 S + 6 = 3 S - 6 \\ S = 12 km \end{array}$

Distance $= \frac{S_{1} \times S_{2}}{(S_{1} - S_{2})} \times t$

From condition - 1

$= \frac{12 \times 15}{3} \times \frac{40}{60} = 40 km$

So. distance is 40 Km.

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