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A man driving a scooter at 30 kmph reaches his destination 7 minutes late to an appointment. If he had drive at 40 kmph he would have reached his destination 3 minutes before time, then his destination is

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20 km

19 km

22 km

11 km

answer is A.

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Detailed Solution

Speed $= 30 k m p h$

Time $= 7 minutes$

Distance $= x k m$

$d = T \times S$

$d = x, t = y$

$d_{1} = (y + \frac{7}{60}) \times 30 \to 1$

$d_{2} = (y - \frac{3}{30}) \times 40 \to 2$

$\frac{60 y + 7}{60} \times 30$ $= \frac{60 y - 3}{60} \times 40$

$(60 y + 7) 3 = 4 (60 y - 3)$

$180 y + 21 = 240 y - 12$

$60 y = 33$

$y = \frac{33}{60} = \frac{11}{20} h r$

$T = \frac{d}{s} = 20 k m$

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