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Q.

A man drops a ball downside from the roof of a tower of height 400 m.  At the same time another ball is thrown upside with speed of 50 ms−1,  they will meet at which height from the base of the tower:

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a

80 m

b

240 m

c

100 m

d

320 m

answer is C.

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Detailed Solution

Let both balls meet at point P after time t

Question Image

The distance travelled by ball A, h1=12gt2

The distance travelled by ball B, h2=ut−12gt2 

h1+h2=400m⇒ut=400,t

= 400/50 = 8 sec

h1=320m and h2=80m

 

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