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A man from the top of a 100-metre high tower sees a car moving towards the tower at an angle of depression of $30^{0}$ . After some time, the angle of depression becomes $60^{0}$ . The distance travelled by the car during the time, is

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$100 \sqrt{3}$

$\frac{200 \sqrt{3}}{3}$

$\frac{100 \sqrt{3}}{3}$

$200 \sqrt{3}$

answer is B.

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Detailed Solution

$\begin{array}{l} \begin{array}{l} T a n 60 = 100 / x \\ X = 100 \sqrt{3} / 3 \\ T a n 30 = 100 / x + y \\ 1 / \sqrt{3} = 100 \times 3 / 100 \sqrt{3} + 3 y \end{array} \\ y = 200 \sqrt{3} / 3 \end{array}$

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