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A man has only $20$ paise coins and $25$ paise coins in his purse. If he has $50$ coins in all totaling Rs. $11.25$ , how many coins of each kind does he have?

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25

coins of each kind

16

coins of each kind

44

coins of each kind

32

coins of each kind

answer is A.

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Detailed Solution

Given that, a man has 20 paise coins and 25 paise coins.
Let no of

20

paise coins

= x

No of

25

paise coins

= y

According to the question

x + y = 50

\Rightarrow x = 50 - y

……….(1)
And

20 x + 25 y = 1125

\Rightarrow 4 x + 5 y = 225

……………(2)
Substituting the value of

x

from equation (1),

\Rightarrow 4 (50 - y) + 5 y = 225

…………….(3)

\Rightarrow 200 - 4 y + 5 y = 225

\Rightarrow y = 25

Substituting

y = 25

in equation (1),

\Rightarrow x + 25 = 50

\Rightarrow x = 25

Thus, no. of

20

paise coins

= 25

and no. of

25

paise coins

= 25

.
Therefore, option (1) is correct.

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A man has only 20 paise coins and 25 paise coins in his purse. If he has 50 coins in all totaling Rs. 11.25, how many coins of each kind does he have?

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A man has only $20$ paise coins and $25$ paise coins in his purse. If he has $50$ coins in all totaling Rs. $11.25$ , how many coins of each kind does he have?