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A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field, the distance he has to walk to reach the field and the magnitude of displacement from his house to the field respectively are

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110m, 50m

75m, 110m

90m, 75m

50m, 110m

answer is B.

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Detailed Solution

$Distance = AC + CD + DE = 50 + 40 + 20 = 110 m$

$Displacement (AE) = \sqrt{{(40)}^{2} + {(30)}^{2}} = 50 m$

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