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Q.

A man has twice the mass of a boy and has half the kinetic energy of the boy. The ratio of the speeds of the man and the boy must be

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a

1 : 4

b

2 : 1

c

1 : 2

d

4 : 1

answer is D.

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Detailed Solution

K.Eman=12(K.E)boy

⇒12Mu2=1212mv2=1212M2v2=18Mv2

⇒uv=12

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