A man having the genotype EEFgGgHH can produce P number of genetically different sperms, and a woman of genotype liLLMmNn can generate Q number of genetically different eggs. Determine the values of P and Q.

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P=4, Q=4

P=4, Q=8

P=8, Q=4

P=8, Q=8

answer is B.

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Detailed Solution

The genotype of an organism can be defined as the sum total of the genetic material present in the cell of an organism. Genotypes are not susceptible to any change with respect to the external environment.

An organism can produce a variety of gametes depending on the types of alleles that are present in the genome. The type of gametes that can be produced by an organism can be calculated by 2ⁿ. In this formula “n” is the number of heterozygous alleles that are present in an organism. In this question the man has to genotype EEFfGgHH. In this genotype two alleles are present in heterozygous form.

Hence the number of types of gametes that can be formed is 2² = 4.

On the other hand the woman has the genotype IiLLMmNn. The number of alleles present in heterozygous forms are 3. Hence the number of types of gametes that can be formed are 2³= 8.

Hence the correct option is B.

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