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Q.

A man in a lift feels an apparent weight W when the lift is moving up with a uniform acceleration of 1/3 rd of the acceleration due to gravity. If the same man were in the same lift now moving down with a uniform acceleration that is 1/2 of the acceleration due to gravity, then his apparent weight is

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a

W8

b

3W4

c

5W8

d

3W8

answer is A.

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Detailed Solution

While going up N=mg+mg3=4mg3=W

While going down N1=mg-mg2=mg2=3W8

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