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Q.

A man invites 10 friends for a dinner party. In how many they can be seated around a circular table so that two particular friends on either side of man?

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a

9!

b

8!

c

10!

d

8!×2!

answer is D.

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Detailed Solution

Let M be the man and F1, F2 be two particular friends

F1MF2 considered to be a single person

We have 9 in all

They can be arranged in 8! and F1, F2 can be interchange in 2 ways

Total =8!×2.

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