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Q.

A man is known to speak truth 3 out of 4 times. Find the probability that he lies.


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a

3 4  

b

1 4  

c

1 2  

d

1   

answer is B.

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Detailed Solution

It is given that a man speaks truth 3 out of 4 times. He throws a die and a number other than six comes up.
For an event E and not getting E, sum of probabilities is 1.
P(E)+P( E ¯ )=1  
Therefore, the probability that a man speaks the truth is 34 .
Let E be an event that he speaks truth.
So, E ¯   is the event that he lies.
Therefore, its probability is,
P(E)+P( E ¯ )=1 3 4 +P( E ¯ )=1 P( E ¯ )=1 3 4 P( E ¯ )= 1 4  
Thus, the probability that he lies is 1 4  .
So, the correct option is 2.
 
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