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Q.

A man is trying to cross a river flowing at a speed of  5ms1   to have least possible displacement by swimming at an angle of 143°  to the stream. The drift he suffers when he is crossing the same river in least possible time is (width of river = 1 km)

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a

800 m

b

200 m

c

160 m

d

400 m

answer is B.

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Detailed Solution

sin500=VrVbr  ,   45=5VbrVbr=254

For shortest time :

t=dVbr= 160 seconds

Drift BC  =Vr×t=5×160=800m  

 

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