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A man is watching two trains one leaving and the other coming in with equal speeds of $4 m / \sec .$ If they sound their whistles each of frequency $240 H z$ , the number of beats heard by the man ( velocity of sound in air $= 320 m / \sec$ ) will be equal to

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Detailed Solution

$\begin{array}{l} \frac{Δ n}{n} = \frac{2 V s}{V} \\ \frac{Δ n}{240} = \frac{2 \times 4}{320} \\ Δ n = 6 \end{array}$

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