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Q.

A man lifts 20 kg of mass up to a height of 1.6 m. What is the work done by the man? Assume g= 10 m/s2.


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a

220 J

b

320 J

c

120 J

d

None of the above 

answer is B.

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Detailed Solution

The work done by the man is 220 J.
We know that the work done equals the energy consumed by the object. Here the energy consumed is due to the change in the object's position. "the potential energy is the energy possessed by an object due to its position relative to other objects". So the potential energy will be counted here.
Work done = potential energy
⇒            =mgh 
Where m is the mass of the object, g is the acceleration due to gravity, h is the height of the object.
Given data:
Mass, m=20 kg
Height, h=1.6 m
g=10 m/s2 
work done= 20×1.6×10
⇒          = 320 J
 
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