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Q.

A man lifts $20 kg$ of mass up to a height of $1.6 m$ . What is the work done by the man? Assume $g = 10 m / s^{2}$ .

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a

220 J

b

320 J

c

120 J

d

None of the above

answer is B.

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Detailed Solution

The work done by the man is

220 J

.
We know that the work done equals the energy consumed by the object. Here the energy consumed is due to the change in the object's position. "the potential energy is the energy possessed by an object due to its position relative to other objects". So the potential energy will be counted here.

Work done = potential energy

\Rightarrow

= mgh

Where

m

is the mass of the object,

g

is the acceleration due to gravity,

h

is the height of the object.
Given data:
Mass,

m = 20 kg

Height,

h = 1.6 m

g = 10 m / s^{2}

work done = 20 \times 1.6 \times 10

\Rightarrow

= 320 J

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